Quantity calculation for ingredients of concrete
How to calculate the required quantity of ingredients for 1m³ concrete of grade M20 (Volume batch)?
Mix ratio for M20 is 1:1.5:3 (Cement: Fine aggregate: Coarse aggregate)
Volume of compacted wet concrete = 1m³
For 1m³ of compacted wet concrete we have to add extra 53% of dry ingredients
So total volume of dry ingredients = 1.53m³
Cement = (1 / (1+1.5+3)) * 1.53 = 0.278m³
2.Fine Aggregate (Sand)
Sand = (1.5 / (1+1.5+3)) * 1.53 = 0.417m³
Coarse aggregate = (3 / (1+1.5+3)) * 1.53 = 0.834m³
Required quantity of concrete ingredients is as follows
Cement = 0.278m³
Fine aggregate = 0.417m³
Coarse aggregate = 0.834m³
Note: Cement will be procured in bags.
Cement = 0.278*30 (For 1m³ of concrete 30 bags of cement required) = 8.34 bags